RCC Sheet 18

1) Question.

In submerged backfill, the sand fill behind the retaining wall
Answer.
- 1
  
  is dry
- 2
  
  is saturated with water
- 3
  
  has uniformed surcharge
- 4
  
  has sloping surface
Answer: 2

Explanation:
2) Question.

The total active earth pressure acts at ............................ above the base of the retaining wall
Answer.
- 1
  
  H/2
- 2
  
  H/3
- 3
  
  H/4
- 4
  
  H/6
Answer: 2

Explanation:
3) Question.

The total active earth pressure ( $p_{a}$ ) or the resultant pressure per unit length of the retaining of its given by
Answer.
- 1
  
  $p_{a} = \frac{w H^{2}}{2} (\frac{1 + \cos ϕ}{1 - \sin ϕ})$
- 2
  
  $p_{a} = \frac{w H^{2}}{2} (\frac{1 - \sin ϕ}{1 + c o s ϕ})$
- 4
  
  $p_{a} = \frac{w H^{2}}{2} (\frac{1 + \cos ϕ}{1 - \cos ϕ})$
Answer: 3

Explanation:
4) Question.

According to Rankin's theory, the intensity of active earth pressure ( $p_{a}$ ) trying to move the retaining wall of height H away from the back fill is given by
Answer.
- 1
  
  $p_{a} = w H (\frac{1 + \cos ϕ}{1 - \sin ϕ})$
- 2
  
  $p_{a} = w H (\frac{1 - \sin ϕ}{1 + \cos ϕ})$
- 3
  
  $p_{a} = w H (\frac{1 - \sin ϕ}{1 + \sin ϕ})$
- 4
  
  $p_{a} = w H (\frac{1 + \cos ϕ}{1 - \cos ϕ})$
Answer: 3

Explanation:
where w = unit weight of soil, and $ϕ$ = angle of internal friction for the back fill
5) Question.

According to Rankine's theory as applied to retaining walls
Answer.
- 1
  
  the soil mass is semi -infinite, homogeneous, dry and cohesionless
- 2
  
  the back of the retaining wall is vertical and smooth
- 3
  
  the retaining wall yields about the base
- 4
  
  all of the above
Answer: 4

Explanation:
6) Question.

A pile of length L carring uniformly distributed load, is suspended at two points. the hogging bending moment at the points of suspension will be equal to sagging bending moment at the middle of pile, if the point of suspension from either end of a pile is equal to
Answer.
- 1
  
  0.15 L
- 2
  
  0.207 L
- 3
  
  0.312 L
- 4
  
  0.41 L
Answer: 2

Explanation:
7) Question.

If the maximum bending moment of a pile of length L carrying uniformly distributed load w per unit length is $\frac{w L^{2}}{90}$ , then the pile is suspended at
Answer.
- 1
  
  one point
- 2
  
  two points
- 3
  
  three points
- 4
  
  four points
Answer: 3

Explanation:
8) Question.

When a pile length L carring unformly distributed load w per unit length is suspended at two points, then the maximum bending moment at the points of suspension will be
Answer.
- 1
  
  $\frac{w L^{2}}{16}$
- 2
  
  $\frac{w L^{2}}{47}$
- 3
  
  $\frac{w L^{2}}{90}$
- 4
  
  $\frac{w L^{2}}{118}$
Answer: 2

Explanation:
9) Question.

When a pile of length L carring uniformly distributed load w per unit length is suspended at one point, then the maximum bending moment at the points of suspension will be
Answer.
- 1
  
  $\frac{w L^{2}}{2}$
- 2
  
  $\frac{w L^{2}}{4}$
- 3
  
  $\frac{w L^{2}}{8}$
- 4
  
  $\frac{w L^{2}}{16}$
Answer: 3

Explanation:
10) Question.

Which of the following statement is wrong ?
Answer.
- 1
  
  The volume of lateral reinforcement provided in provided in reinforced piles should not be less than 0.2% of the gross volume of the pile.
- 2
  
  The centre to centre spacing of lateral reinforcement in reinforced piles should not exceed half the width of the pile.
- 3
  
  when the pile has to penetrate hard stratum, the lateral reinforcement at the top of the pile for a distance of three times the width, should be in the form of helix
- 4
  
  none of the above
Answer: 4

Explanation:

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