Steel Design Sheet 36

1) Question.

The bearing length of web (B) under concentrated load is given by

[ b= Length of bearing plate, and h= Depth of root of fillet from the outer surface of flange]
Answer.
- 1
  
  $B = b + h \sqrt{3}$
- 2
  
  $B = b - h \sqrt{3}$
- 3
  
  $B = b + 2 h \sqrt{3}$
- 4
  
  $B = b - 2 h \sqrt{3}$
Answer: 3

Explanation:
2) Question.

The web crippling
Answer.
- 1
  
  is a failure of web in direct crushing under concentrated load
- 2
  
  means the stress concentration due to bottle-neck condition at the web toe of the fillet under or over heavy load concentrations
- 3
  
  is a localised bearing stress caused by the transmission of compression from the comparatively wide flange to the narrow web
- 4
  
  all of the above
Answer: 4

Explanation:
3) Question.

The allowable bearing stress for rolled steel beams is
Answer.
- 1
  
  $128 N / m m^{2}$
- 2
  
  $156 N / m m^{2}$
- 3
  
  $189 N / m m^{2}$
- 4
  
  $228 N / m m^{2}$
Answer: 3

Explanation:
4) Question.

In rolled steel beams, the failure of web occurs
Answer.
- 1
  
  at the concentrated loads
- 2
  
  at the supports
- 3
  
  at a point where deflection is maximum
- 4
  
  both (a) and (b)
Answer: 4

Explanation:
5) Question.

When the radius of gyration of a tension member is r, the maximum allowable bending stress in tension is $σ_{^{b}}$ , the distance to the extreme fibre from the neutral axis is y and the bending moment is M when the member is subjected to pure bending, then the cross-sectional area (A) is given by
Answer.
- 1
  
  $A = \frac{M y}{σ_{b} . r^{2}}$
- 2
  
  $A = \frac{M r^{2}}{σ_{b} . y}$
- 3
  
  $A = \frac{σ_{b} . r^{2}}{M y}$
- 4
  
  $A = \frac{σ_{b} . y}{M r^{2}}$
Answer: 1

Explanation:
6) Question.

When the tension member is subjected to both axial tension and bending, then it should be proportioned is such a manner that
Answer.
- 1
  
  $\frac{{σ_{t}}^{'}}{σ_{t}} + \frac{{σ_{b}}^{'}}{σ_{b}} > 1$
- 2
  
  $\frac{{σ_{t}}^{'}}{σ_{t}} + \frac{{σ_{b}}^{'}}{σ_{b}} < 1$
- 3
  
  $\frac{σ_{t}}{{σ^{'}}_{t}} + \frac{{σ_{b}}^{'}}{σ_{b}} > 1$
- 4
  
  $\frac{{σ_{t}}^{'}}{σ_{t}} + \frac{σ_{b}}{{σ^{'}}_{b}} > 1$
Answer: 2

Explanation:
7) Question.

Indian standards recommend that for a splice plate, rivets or bolts carrying calculated shear stress through a packing greater than 6 mm thick should be increased above the number required by normal calculations by
Answer.
- 1
  
  1.5% for each 1 mm thickness of packing
- 2
  
  2.5% for each 1 mm thickness of packing
- 3
  
  1.5% for each 2 mm thickness of packing
- 4
  
  2.5% for each 2 mm thickness of packing
Answer: 4

Explanation:
8) Question.

The load, which produces the average axial tensile stress in the section equivalent to the maximum combined stress at the extreme fibre of the section, is known as
Answer.
- 1
  
  equivalent axial tensile load
- 2
  
  buckling load
- 3
  
  crippling load
- 4
  
  critical load
Answer: 1

Explanation:
9) Question.

A single angle steel tie is connected to gusset plates at both ends using rivets. For determining the load carrying capacity of the tie, the allowable tensile stress should be multiplied by the
Answer.
- 1
  
  gross area of the angle
- 2
  
  net area of the angle
- 3
  
  net area of the connected leg plus the effective area of the outstanding leg
- 4
  
  effective area of the connected leg plus the gross area of the outstanding leg
Answer: 2

Explanation:
10) Question.

In order to determine the gross-sectional area of a tension member consisting of two laced channels, the allowance for holes is made as
Answer.
- 1
  
  two holes from each flange
- 2
  
  two holes from each web
- 3
  
  two holes from each channel web or one hole from each flange, whichever is more
- 4
  
  none of these
Answer: 3

Explanation:

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